2x^2+4x(120/x^2)=A

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Solution for 2x^2+4x(120/x^2)=A equation: 



2x^2+4x(120/x^2)=

We move all terms to the left:

2x^2+4x(120/x^2)-()=0



Domain of the equation: x^2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2x^2+4x(120/x^2)=0

We multiply parentheses

2x^2+480x^2=0

We add all the numbers together, and all the variables

482x^2=0

a = 482; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·482·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{964}=0$

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